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Summarize the methods of solving chemistry problems in senior high school, please, thank you.
1. correlation method is a clever application of calculation based on chemical equations. The core idea of solving the problem is the conservation of mass in chemical reactions, and there is the most basic proportion (quantity) relationship between reactants and products. 2. Equation or equation group method is the most commonly used method in chemical calculation, and its problem-solving skills are also the most important calculation skills. Third, the conservation method Since the chemical equation can express the quantitative relationship between the quantity, mass and gas volume of substances between reactants and products, it must reflect that the number of atoms, charges, gain and loss electrons and total mass are conserved before and after the chemical reaction. Clever application of conservation law can often simplify the steps of solving problems, solve problems accurately and quickly, and get twice the result with half the effort. Fourth, the difference method finds out some difference before and after the chemical reaction and the essence and relationship of this difference, and lists the method to solve the proportional formula, which is the difference method. The difference may be poor quality, air volume, pressure, etc. The essence of difference method is to skillfully use calculation according to chemical equations. Its greatest advantage is that as long as the difference is found, the amount consumed by each reactant or the amount produced by each product can be found. 5. Average method Average method is a clever problem-solving method, and it is also an important problem-solving thinking and method. Extreme value method of intransitive verbs is a method of chemical calculation by using mathematical limit knowledge, that is, extreme value method. Seven. Cross method If A and B are used to represent the amounts of two components of binary mixture respectively, the total amount of mixture is A+B (for example, mol). If xa and xb are used to represent the characteristic quantities (such as molecular weight) of the two components and X is used to represent the characteristic quantities (such as average molecular weight) of the mixture, there are: the cross method is a special method in the calculation of binary mixture (or composition), which evolved from the calculation of binary linear equation. If the two groups of components and the average value of these two quantities are known, the proportional relationship between these two quantities can be calculated by crossing method. The key to using the cross method is to conform to the binary linear equation relationship. What calculation is it used for? Clearly using the cross method to calculate the conditions can list binary linear equations, and special attention should be paid to avoid the abuse of unclear chemical meaning. The crossover method is mainly used for: ① calculating the atomic number ratio of two isotopes. ② Calculation of mixture composition and average formula. ③ Calculation of mixed hydrocarbon composition. (Secondary content) ④ Calculate the mass fraction or solution dilution of a certain component. Example 7 It is known that there are two isotopes of iridium in nature, the mass numbers are 19 1 and 193 respectively, and the average atomic weight of iridium is 192.22. The atomic number ratio of these two isotopes should be [] A.39 ∶ 61b.61∶ 39c.1∶1d.39 ∶1. This problem can be solved by a binary linear equation, but the cross method is the fastest: when solving the calculation problem, if the conditions for setting the problem are sufficient, it can be directly calculated and solved; If the conditions are not sufficient, we should use the methods of discussion, calculation and reasoning to solve the problem. Example 8 Fill a 30mL measuring cylinder with the mixed gas of NO2 and O2, stand upside down in water to make the gas fully react, and finally leave 5mL of gas. What is the volume of oxygen in the original mixed gas? The last 5mL gas may be O2 or NO, which needs to be discussed and analyzed. Solution (1) The last remaining 5mL gas may be O2; It may also be negative. If it is NO, NO2 exceeds the standard 15mL. Assume that the volumes of NO2 and O2 in 30mL original gas mixture are X, and Y4NO2+O2+2H2O = 4NO3. The volume of oxygen in the original gas mixture may be10ml or 3ml. Solution (2): Let the volume of oxygen in the original mixture be y(mL) (1) and let O2 be excessive: according to 4NO2+O2+2H2O = 4NO3, the number of electrons obtained by O2 is equal to the number of electrons lost by NO2. (y-5)×4=(30-y)× 1, y= 10(mL) (2) If NO2 is excessive: 4NO2+O2+2h2o = 4NO3 4y3no2+H2O = 2hno3+NO because in all (30-y) Evaluation solution (2) According to the conservation of gain and loss electrons, Avon Gadereau's law is used to transform information, and the volume number is converted into the quantity of matter to simplify the calculation. All redox reactions can generally be calculated by the conservation of electron gain and loss. No matter the solution (1) or the solution (2), it is necessary to combine the discussion method to solve the problem because of insufficient conditions. 4y+5×2=(30-y-5)× 1。 Y=3 (ml). The volume of raw oxygen can be10ml or 3ml. Some main chemical calculation skills are introduced one by one. There is no fixed method model to solve the problem. But from the basic steps of solving chemical problems, candidates should establish a certain basic thinking mode. "Showing information, ten basic knowledge and ten logical thinking" is such a thinking mode, which also reflects the basic ability requirements of solving problems, so some people call it "ability formula" for solving problems. I hope that students can establish a basic thinking mode to solve problems, deepen their foundation, activate their thinking, optimize their quality, and jump up to pick the fruits of wisdom. Listen and summarize the following basic steps of chemical calculation: (1) Carefully examine the questions and mine information. (2) Flexible combination and application of basic knowledge. (3) Fully think and form a problem-solving idea. (4) Choose a method to solve the problem correctly.