Yes, as long as the magnification is correct, given e greater than 0, there is n-make, when n >; N makes the absolute value of (4n) 2/(n squared -n) -4 less than e, and the key is that as long as this n can be found, it is OK, because this is the limit of the sequence, and finally n should take the integer part.

In other words, you found this n, so that when n >；; When n, for any E greater than 0, the absolute value of (4n) 2/(n squared -n) -4 is less than that of E.