So angle A= angle ABC AB=BC
Because BD=AE
So the triangle ABE is equal to the triangle BDC.
So BE=DC
Let ∠ BCD = x
Because ABE≌BDC
So ∠ BCD = ∠ Abe = X.
In the triangle BDC
∠BDC = 180-60-x = 120-x
In the triangular BDP
∠DPB = 180-∠DBP-∠BDP = 180-∠ABE-∠BDC
= 180 x-( 120-x)= 60
Because EH⊥DC
So ∠ PEH = 30.
There is BP=PH again.
∠PBH=∠PHB
∠∠PBH+∠PHB =∠EPh = 60
∴∠PBH=30
∴BH=EH
EBH =∠BEH =∠ BHP Billiton =30
∴∠HBC+∠BCH=30
∴∠hbc=30 x
It is not difficult to prove that ∠ ACD = Y.
Triangle ADC≌BDC
∴∠EBC=∠ACD=y
∠EBC=∠EBH+∠HBc=30 +(30 -x )=y
∠BCA=∠BCD+∠DCA=x +y =60
Solve the equation X = 15 y = 45.
EH⊥CD again
∴EH=HC
∴BE=DH+HE should be able to understand. If you look closely, you should be fine.