So angle A= angle ABC AB=BC

Because BD=AE

So the triangle ABE is equal to the triangle BDC.

So BE=DC

Let ∠ BCD = x

Because ABE≌BDC

So ∠ BCD = ∠ Abe = X.

In the triangle BDC

∠BDC = 180-60-x = 120-x

In the triangular BDP

∠DPB = 180-∠DBP-∠BDP = 180-∠ABE-∠BDC

= 180 x-( 120-x)= 60

Because EH⊥DC

So ∠ PEH = 30.

There is BP=PH again.

∠PBH=∠PHB

∠∠PBH+∠PHB =∠EPh = 60

∴∠PBH=30

∴BH=EH

EBH =∠BEH =∠ BHP Billiton =30

∴∠HBC+∠BCH=30

∴∠hbc=30 x

It is not difficult to prove that ∠ ACD = Y.

Triangle ADC≌BDC

∴∠EBC=∠ACD=y

∠EBC=∠EBH+∠HBc=30 +(30 -x )=y

∠BCA=∠BCD+∠DCA=x +y =60

Solve the equation X = 15 y = 45.

EH⊥CD again

∴EH=HC

∴BE=DH+HE should be able to understand. If you look closely, you should be fine.