Let the total number of finishing laboratories be x, then the speed of teacher Zhang is x/50 and that of teacher Li is x/30.

Teacher Zhang's 30-minute homework is x/50×30=3x/5.

The remaining workload is x-3x/5=2x/5.

Teacher Zhang and Miss Li * * * have the same sorting speed, which is x/50+x/30=8x/ 150.

Time required to complete the work t = (2x/5)/(8x/150) = 7.5 <10 minute.

You can complete the sorting.

I hope this helps.