=( 1/2)∫e^x( 1+cos2x)dx，
= ( 1/2)∫(e^x+e^x*cos2x) dx
=( 1/2)∫e^x dx+( 1/2)∫e^x*cos2x dx
= 1/2*e^x+( 1/2)∫e^x*cos2x
= 1/2e^x+( 1/2)*e^x*(cos2x+2sin2x)/( 1+2？ ) formula: ∫ e (ax) * cos (bx) = e (ax) * [acos (bx)+bsin (bx)]/(a? +b？ )
= 1/2e^x+( 1/ 10)*[e^x*(cos2x+2sin2x)+c