The slope of the straight line between point A and point B is-1; Point oblique instead of point a

y

= 2-x；

(2)A(0，2)B(2，0)

A and b were brought in at two o'clock.

Get b =-3 and c = 2；;

(3) Points (2,5) and (4,5) are brought into parabola Y = AX2+BX+C.

5=4a

2b

c

5= 16a

4b

c

The result of subtraction is b=-6a.

Axis of symmetry x=3

(4) The function is not given

(5)y=a(x+k)2+k

Obviously, when y takes the maximum value, it is the image vertex (-k, k).

The straight line where the vertex of the image is located is y =-X.