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The third grade of elementary school seeks simple and easy-to-understand answers to math problems in the third grade.
1. Enlarge the sum of the ages of Party A, Party B and Party C by 2 times, that is, 2A+2B+2B =94x2= 188.

Change 2A to C, because 2A is 5 more than C, so 188 minus 5 is changed to C,

Similarly, replacing 2 B with c and subtracting 19 from 188 can also be replaced with c,

So: C+C +2 C = 188-5- 19.

4 C = 164,

c = 4 1a =(4 1+5)÷2 = 23 B = 94-4 1-23 = 30。