The center of the circle is on the vertical line of MN.

The midpoint of MN is (4,2) and the slope is (2-2)/(5-3)=0.

∴MN is parallel to the X axis, and the perpendicular bisector of∴ Mn is: x=4.

X=4 and Y = 2x-3 are used to solve the equation simultaneously: x=4 and y=5.

∴ The center coordinate is O (4 4,5)

And | om | 2 = (5-4) 2+(2-5) 2 = 10.

The equation of a circle is: (x-4) 2+(y-5) 2 = 10.

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