So the angle BDF = 60°, BF= root number 3 *DF≈ 173.2m, CF=DE= root number 3 * AE ≈173.2m.
1) If the bridge is built in D, the distance between AB is AD+DF+FB = 200+100+173.2 = 473.2m..
2) If the bridge is repaired in E, the distance between AB is AE+EC+CF+FB =100+100+173.2+173.2 = 546.2m..
Therefore, repairing the bridge in D can make the distance between AB shortest, and the shortest distance is 473.2m m..