∴b=3/2 and k=-3/2.
-k+b=3 b=3/2
The resolution function of BC is y=-3/2x+3/2.
② Let the resolution function of OC line be y 1=ax.
Replace C(- 1, 3)
The solution is a=-3.
∴y 1=-3x
∫ The straight line passing through point E (-2,0) is parallel to OC and intersects with straight line y=-3/2x+3/2 at point D.
The analytical formula of ∴ straight line ED is y2=-3(x+2)=-3x-6.
When y 1=y2, x=-5 y=9.
That is, d (-5,9)
③ if d crosses, the DF⊥x axis is in f (-5,0), if c crosses, the CM⊥x axis is in M(- 1, 0).
S quadrilateral CDEO=S trapezoid DFOC-S△DFE+S△CMO= 12.
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