∴b=3/2 and k=-3/2.

-k+b=3 b=3/2

The resolution function of BC is y=-3/2x+3/2.

② Let the resolution function of OC line be y 1=ax.

Replace C(- 1, 3)

The solution is a=-3.

∴y 1=-3x

∫ The straight line passing through point E (-2,0) is parallel to OC and intersects with straight line y=-3/2x+3/2 at point D.

The analytical formula of ∴ straight line ED is y2=-3(x+2)=-3x-6.

When y 1=y2, x=-5 y=9.

That is, d (-5,9)

③ if d crosses, the DF⊥x axis is in f (-5,0), if c crosses, the CM⊥x axis is in M(- 1, 0).

S quadrilateral CDEO=S trapezoid DFOC-S△DFE+S△CMO= 12.