(4)5x-5y+5z (5)-5a？ +25a-5a(6)2a(b+ c)-3(b+ c)(7)(a b+ a)+(b+ 1)

(8)-4m？ + 16m？ -28m (9) 16x-25x？ y？ ( 10)36m？ a-9m？ Answer? -36m？

√32-3√ 1/2+√2

√ 12+√27/√3-√ 1/3×√ 12

√50+√30/√8-4

(√6-2√ 15)×√3-6√ 1/2

√2/3-4√2 16+43√ 1/6

√8+√30-√2

√40-5√ 1/ 10+√ 10

√2+√8/√2

√2/9+√50+√32

( 1-√3)(√3+2)

(√8+3√6)÷√2-√3×√0.7

(-3+√6)(-3-√6)-(√3- 1/√3)?

? √0. 125-√3 1/ 16+? √( 1-7/8)?

√2/3-√2 16+42√ 1/6

Solve the equation √3 X- 1=√2 X.

Find x

{√5 X-3√ Y= 1}

{√3 X-√5 Y=2}

Note: all x's are not in the root symbol.

√( 1/2x)^2+ 10/9x^2

=√[ 1/(4x^2)+ 10/(9x^2)]

=√49/36x^2

If x>0, =7/(6x)

If x < 0, =-7/(6x)

√a^4mb^2n+ 1

=√(a^2mb^n)^2+ 1

=a^2mb^n+ 1

√(4a^5+8a^4)(a^2+3a+2)

=√[4a^4(a+2)][(a+2)(a+ 1)]

=√[4a^4(a+2)^2(a+ 1)]

=2a^2(a+2)√(a+ 1)

. 3√( 1/6)-4√(50)+30√(2/3)

Answer 3√( 1/6)-4√(50)+30√(2/3)

= 3×√6/6-4×5√2+30×√6/3

=√6/2-20√2+ 10√6

2.( 1- radical number 2)/2 times (1+ radical number 2)/2

The problem is this: one-half MINUS the root number 2 times one-half plus the root number 2.

Answer: (1- root number 2)/2 times (1+ root number 2)/2.

=( 1-√2)*( 1-√2)/4

=( 1-2)/4

=- 1/4

1.3 √ (1/6)-4 √ (50)+30 √ (2/3) Answer 3 √ (1/6)-4 √ (50)+30 √ (2/3) = 3 × Twice (1+ root number 2)/2 The question is as follows: 1/2 minus root number 2 1/2 plus root number 2 Answer: (1- root number 2)/2 = kloc-0//2x)^2+ 10/9x^2]=√(x^2/4+ 10x^2/9)=√(9x^2/36+40x^2/36)=√(49x^2/36)= 7x/6； 4.√ A 4mb 2n+ 1 (A and B are both positive numbers) [√ (A 4mb 2n)]+ 1 (A and B are both positive numbers) = A2MbN+1; 5.√(4a^5+8a^4)(a^2+3a+2)(a>； = 0)√[(4a^5+8a^4)(a^2+3a+2)](a>； = 0)= √[ 4a 4(a+2)(a+ 1)]=√[(2a 2)2(a+2)2(a+ 1)]= 2a 2(a+)①5√8-2√32+√50 = 5 * 3√2-2 * 4√2+5√2 =√2( 15-8+5)= 12√2=(3√6) ^2-2*3√6*√4+(√4)^2 =54- 12√6+4 =58- 12√6 ⑩( 1+√2-√3)( 1-√2+√3) =[ 1+(√2-√3)][ 1-(√2-√3)] = 1-(√2-√3) ^2 = 1-(2+3+2√6) =-4-2√6 1.=5√5 - 1/25√5 - 4/5√5 =√5*(5- 1/25-4/5) =24/5√5 2.=√ 144+576 =√720 = 12√5 3.) √(8/ 13) ^2-(2/ 13)^2 = √(8/ 13+2/ 13)(8/ 13-2/ 13) =(2/ 13)√ 15