Mathematical application problems of freshmen in summer vacation in Xiaoshengchu
20 minutes = 1/3 hours, 24 minutes =2/5 hours. Let the original speed be x kilometers. We assume that everyone has traveled long enough. Then, if A walks more (x 6) *1/3 = x/3+2, and B walks less (x-5)*2/5=2x/5-2, the distance difference is x/3+2+2x/5-2 =1. 1 1=x/ 15 Equation 6 * (x/15-1/3) = (1/3) * x (Note: accelerate 6 km in (x/60).