Proof: Right = 4 (3-log27)/(3+log27) = 4 (log12? -log27)/(log 12? +log27)
=[4 log( 1728/27)]/[log( 12? ×27)]=(4log64)/(log36? )=(4log2? )/(log6? )
= 4 log 2)/(log 6)=(log 16)/(log 6)= log? 16= left.