Proof: Right = 4 (3-log27)/(3+log27) = 4 (log12? -log27)/(log 12？ +log27)

=[4 log( 1728/27)]/[log( 12？ ×27)]=(4log64)/(log36？ )=(4log2？ )/(log6？ )

= 4 log 2)/(log 6)=(log 16)/(log 6)= log？ 16= left.