Three questions at a time? Question 1: It is concluded from the condition that a2a3=a 1a4= 1/2, so (1/a2)( 1/a3)=2 and 1/A2+/kloc-. 1/a3= 1, that is, a2A3= 1, so q = a3/a2 = 2a3+...+A8 = a3 (1-q6)/(1-q) = 2. = A77 =1286 = (27) 6 = (26) 7A7 = 26 = 64 If the arithmetic difference between a6 and A7 is 48, it is 2×48=a6+a7 a6+64=96 a6=32, and the public ratio is Q = A7. Sn =/kloc-0 /× (2-1)/(2-1) = 2-1Question 3: a2=2, A5= 1/4, So Q3 = A5/A2 =1/8q =1/2A1= A2/Q = 4ana (n+1) = A1Q (n ..+ana (n+/0).

Satisfied, please adopt.