LOA+△L = v 0△t+v 0(t B-△t)- 12a(t B-△t)2
On the way from O to C:
LOA+2△L = v 0△t+v 0(tC-△t)- 12a(tC-△t)2
Simultaneous equation:
v0= 16m/s
a=2m/s2
(2) The distance from the start to the stop of the car:
x=v0△t+v022a
Available x=72m
Therefore, when the car stops moving, the front end face of the car leaves D between CDs.
LOA+3△L-s-x=44+36-2-72=6m。
Answer: (1) The speed before braking is 16m/s,
The acceleration a after braking is 2m/S2;
(2) When the car stops moving, the distance between the front of the car and D is 6m.