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Functional learning plan
(1) when the advertising fee is x (one hundred thousand yuan), the sales volume is 10y=-x? +6x+ 10 (100,000 pieces)

∴ s=(3-2)*(-x? +6x+ 10)-x=-x? +5x+ 10 (one hundred thousand yuan) (x≥0)

(2)s=-x? +5x+ 10=-(x-2.5)? + 16.25

When the advertising fee100000 to 300000 yuan, that is, x∈ 1, 3.

According to the function image, when x ∈ 1, 2.5, the function s is monotonically increasing.

Therefore, when the advertising fee is 6,543,800+to 250,000, the company's annual profit will increase with the increase of advertising fee.

(3) When x=2.5, the maximum value of function S is smax= 16.25 (one hundred thousand yuan).

Therefore, when the advertising fee is 250,000 yuan, the company gets the highest annual profit of 6,543,800 yuan+0,625 yuan.