Think about solving problems:
According to the known conditions, a table is 288 yuan more than a chair, which is exactly (10- 1) times the price of a chair, so the price of a chair can be obtained. According to the price of chairs, we can get the price of a table.
Answer:
Solution: the price of the chair:
288( 10- 1)= 32 (yuan)
The price of a table:
32× 10=320 (yuan)
A table 320 yuan, a chair 32 yuan.
2, 3 boxes of apples weigh 45 kilograms. A box of pears is 5 kilograms heavier than a box of apples. How much do three boxes of pears weigh?
Think about solving problems:
You can first find out that the weight of 3 boxes of pears is more than that of 3 boxes of apples, plus the weight of 3 boxes of apples, which is the weight of 3 boxes of pears.
Answer:
Solution: 45+5×3=45+ 15=60 (kg)
Three boxes of pears weigh 60 kilograms.
3. Party A and Party B walked across two places at the same time. Four hours later, they met four kilometers from the midpoint. A is faster than B. How many kilometers is A faster than B per hour?
Think about solving problems:
According to the meeting at a distance of 4 kilometers from the midpoint, and the speed of A is faster than that of B, it is known that A walks 4×2 kilometers more than B, and it takes 4 hours to meet. You can work out how many kilometers A is faster than B per hour.
Answer:
Solution: 4×2÷4=8÷4=2 (km)
A: A is 2 kilometers faster than B per hour.
Li Hua and Zhang Qiang spent the same money on the same kind of pencils. Li Hua asked for 13 pencils, Zhang Qiang asked for 7 pencils, and Li Hua gave Zhang Qiang 0.6 yuan money. How much is each pencil?
Think about solving problems:
According to the fact that two people pay the same money for the same pencil, Li Hua's asking price is 13 and Zhang Qiang's asking price is 7, which shows that each person deserves (13+7)÷2, while Li Hua's asking price is 13, which is three more than his due, so he gave Zhang Qiang and 0.6 yuan money, and then he could ask for the price of each pencil.
Answer:
Solution: 0.6 ÷ [13-(13+7) ÷ 2] = 0.6 ÷ [13-20 ÷ 2] = 0.6 ÷ 3 = 0.2 (.
A: Every pencil is 0.2 yuan.
At 8 o'clock in the morning, two buses, A and B, set off from two stations at the same time and walked in opposite directions. After a while, two buses reached both sides of a river at the same time. Because the bridge over the river is being repaired, vehicles are forbidden to pass. The two cars need to exchange passengers and then return to their respective departure stations by the same route. When they arrived at the station, it was already 2 pm. Car A travels 40 kilometers per hour and car B travels 45 kilometers per hour. How many kilometers are there between these two places? (The exchange time is omitted)
Think about solving problems:
According to the fact that two cars leave two stations at 8: 00 am and return to the original station at 2: 00 pm, the travel time of the two cars can be calculated. According to the speed and driving time of the two cars, the total distance traveled by the two cars can be calculated.
Answer:
Solution: 2 pm is 14 pm.
Round trip time: 14-8=6 (hours)
Distance between the two places: (40+45)×6÷2=85×6÷2=255 (km)
Attendant: The distance between the two places is 255 kilometers.
6, a parallelogram, if only increased by 8 meters, or only increased by 5 meters, then its area increased by 40 square meters. Find the original area of this parallelogram?
Think about solving problems:
According to the increase of only 8 meters at the bottom, the area will increase by 40 square meters. The height of the original parallelogram can be obtained. According to increasing the height of 5 meters and the area of 40 square meters, the bottom of the original parallelogram can be found. The original bottom multiplied by the original height is the required area.
Answer:
Solution: (40÷5)×(40÷8)=40 (square meters)
A: The original area of parallelogram is 40 square meters.
7. There are two warehouses, A and B, each of which stores 32.5 tons of grain on average. The tonnage of grain stored in warehouse A is 5 tons less than that in warehouse B. How many tons of grain are stored in warehouse A and warehouse B respectively?
Think about solving problems:
According to the fact that the tonnage of grain stored in warehouse A is 5 tons less than that in warehouse B, we can know that if the tonnage of grain stored in warehouse A increases by 5 tons, the tonnage of grain stored in warehouse B is 4 times that of warehouse B, and the total grain storage will also increase by 5 tons. If the tonnage of stored grain in warehouse B is regarded as 1 times, the total tonnage of stored grain is (4+ 1) times, from which the tonnage of stored grain in warehouse A and warehouse B can be calculated.
Answer:
Solution: store the grain in warehouse b:
(32.5× 2+5) ÷ (4+1) = (65+5) ÷ 5 = 70 ÷ 5 =14 (ton)
The warehouse stores grain;
14×4-5=56-5=5 1 (ton)
Warehouse A stores 5 1 ton of grain, and warehouse B stores 14 ton of grain.
8. Team A and Team B are repairing a 400-meter-long highway. Team A completed four days from east to west and team B completed five days from west to east. Team a repairs more than team b every day 10 meter. How many meters do Team A and Team B repair every day?
Think about solving problems:
According to the fact that Team A repairs10m more than Team B every day, it can be considered that if Team A repairs for 4 days and Team B repairs for 4 days, the total length will be reduced by 410m, and the length at this time is equivalent to Team B (4+5). From this, we can get the number of meters repaired by team B every day, and then get the number of meters repaired by the two teams every day.
Answer:
Solution: b the number of meters repaired every day:
(400-10× 4) ÷ (4+5) = (400-40) ÷ 9 = 360 ÷ 9 = 40 (meters)
Number of meters repaired by Team A and Team B every day:
40×2+ 10=80+ 10=90 (m)
A: Two teams repair 90 meters every day.
9. The school bought 6 tables and 5 chairs and paid 455 yuan. As we all know, every table is more expensive than every chair. 30 yuan, what's the unit price of each desk and chair?
Think about solving problems:
It is known that each table is more expensive than each chair, 30 yuan. If the unit price of the table is as much as that of the chair, then the total price should be reduced by 30×6 yuan. At this time, the total price is equivalent to the price of (6+5) chairs, from which the unit price of each chair can be obtained, and then the unit price of each table can be obtained.
Answer:
Solution: Price per chair:
(455-30× 6) ÷ (6+5) = (455-180) ÷1= 275 ÷1= 25.
Price per table:
25+30=55 (yuan)
Every table 55 yuan, every chair 25 yuan.
10, a train and a local train leave from A and B respectively at the same time. The express train is 75 kilometers per hour and the local train is 65 kilometers per hour. When we met, the express train traveled 40 kilometers more than the local train. How many kilometers is it between Party A and Party B?
Think about solving problems:
According to the known speed of the two cars, the speed difference can be found, and according to the speed difference between the two cars and the distance between the express train and the local train, the travel time of the two cars can be found, and then the distance between Party A and Party B can be found.
Answer:
Solution: (7+65)×[40(75-65)]
= 140×[40÷ 10]
= 140×4=560 km
A: The distance between A and B is 560 kilometers.
1 1. A glass factory consigned 250 boxes of glass, and the freight for each box was agreed in the contract in 20 yuan. If a box is damaged, it will not only pay the freight, but also compensate 100 yuan. At the time of settlement after delivery, * * * pays the freight of 4,400 yuan. How many cases of glass are damaged in the consignment?
Think about solving problems:
According to the known consignment of 250 cases of glass, the freight for each case is 20 yuan, and the total freight payable can be calculated. According to the damage of each box, not only do you not pay the freight, but you also pay compensation of 100 yuan. The difference between the known payable amount and the actual paid amount is several yuan (100+20), that is, several boxes are damaged.
Answer:
Solution: (20×250-4400)÷( 10+20)
=600÷ 120=5 (box)
A: Five cases are damaged.
12, the first and second squadrons of grade five are going for a spring outing 20 kilometers away from school. The first squadron walks 4 kilometers per hour, and the second squadron rides bicycles, traveling every hour 12 kilometers. The first squadron will leave in two hours, and the second squadron will leave again. How many hours will it take the second squadron to catch up with the first squadron?
Think about solving problems:
Because the first squadron started 2 hours 4×2 kilometers earlier than the second squadron, and the second squadron was (12-4) kilometers earlier than the first squadron leader, we can find out the time when the second squadron caught up with the first squadron.
Answer:
Solution: 4× 2 ÷ (12-4) = 4× 2 ÷ 8 =1(hour)
Answer: The second squadron 1 hour can catch up with the first squadron.
13, a factory shipped a pile of coal. If you burn 1500 kg a day, burn it one day in advance. If we burn 1000 kg a day, we will burn one more day than planned. How many kilograms is this pile of coal?
Think about solving problems:
According to the known conditions, the difference between the total amount of coal burned before and after is (1500+ 1000) kg, which is caused by the difference of (1500- 1000) kg per day. From this, the number of days of planned combustion can be calculated, and then the amount of this pile of coal can be calculated.
Answer:
Solution: The original planned number of days of coal burning:
(1500+1000) ÷ (1500-1000) = 2500 ÷ 500 = 5 (days)
The weight of this pile of coal:
1500× (5-1) =1500× 4 = 6000 (kg)
This pile of coal is 6000 kilograms.
14, Mom sent Xiaohong to the store to buy five pencils and eight exercise books, and gave Xiaohong 3.8 yuan money according to the price. As a result, Xiaohong bought 8 pencils and 5 exercise books and got back 0.45 yuan. How much is a pencil?
Think about solving problems:
The total number of pencils and notebooks that Xiaohong intends to buy is equal to the total number of pencils and notebooks actually bought. The change is 0.45 yuan, which means that (8-5) pencils are counted as (8-5) exercise books, with a difference of 0.45 yuan. From this, we can find out how much the unit price of exercise books is more expensive than pencils. Judging from the total amount of money, eight exercise books are more expensive than eight pencils, leaving (5+8) pencils. Then you can work out the price of each pencil.
Answer:
Solution: How much is each exercise book more expensive than each pencil?
0.45÷(8-5)=0.45÷3=0. 15 (yuan)
Eight exercise books are more expensive than eight pencils;
0. 15×8= 1.2 (yuan)
Price of each pencil:
(3.8-1.2) ÷ (5+8) = 2.6 ÷13 = 0.2 (yuan)
A: Every pencil is 0.2 yuan.
15, the school organized a visit with 360 teachers and students. One bus carries more passengers than one truck 10, and six buses and eight trucks carry the same number of people. How many trucks do you need? How many buses do you need to take?
Think about solving problems:
According to the fact that passenger cars are overloaded with 10 people than freight cars, we can find out the number of people who are overloaded with six passenger cars than six freight cars, that is, the number of people on (8-6) multi-purpose freight cars, and then we can find out how many people are on each freight car and how many people are on each bus.
Answer:
Solution: Number of trucks:
360÷[ 10×6÷(8-6)]
=360÷[ 10×6÷2]
=360÷30= 12 (vehicle)
Number of buses:
360÷[ 10×6÷(8-6)+ 10]
=360÷[30+ 10]
=360÷40=9 (vehicle)
A: There are 12 trucks and 9 buses available.
16, a road construction team undertook the task of building a highway. It was originally planned to repair 720 meters a day, but it was actually repaired 80 meters more than the original plan, so that the actual repair difference 1200 meters can be completed three days in advance. What is the total length of this highway?
Think about solving problems:
According to the plan, the construction is 720 meters per day, and the actual advance length is (720×3- 1200) meters. According to the repair of 80 meters per day, the number of days of repair can be found, and then the total length of the road can be found.
Answer:
Solution: Repair days:
(720× 3-1200) ÷ 80 = 960 ÷ 80 =12 (days)
Total length of highway:
(720+80) ×12+1200 = 800×12+1200 = 9600+1200 =10800 (.
Answer: The total length of this highway is 10800 meters.
17. A shoe factory produces 1800 pairs of shoes, which are packed into 12 cartons and 4 wooden cases respectively. If there are as many shoes in 3 cartons as in 2 wooden boxes. How many pairs of shoes are there in each carton and wooden box?
Think about solving problems:
According to the known conditions, we can find the number of 12 cartons converted into wooden cases. First, we can work out how many pairs are packed in each carton, and then we can work out how many pairs are packed in each carton.
Answer:
Solution: 12 carton is equivalent to the number of wooden cases:
2× (12 ÷ 3) = 2× 4 = 8 (pieces)
The number of shoes in the wooden box is even:
1800÷(8+4)= 18000÷ 12 = 150(double)
Even number of shoes in a box:
150×2÷3= 100 (double precision)
A: Each carton can hold 100 pairs of shoes, and each wooden box can hold 150 pairs of shoes.
18, a construction site brought in a batch of sand and cement, and the number of bags of sand brought in was twice that of cement. Use 30 bags of cement and 40 bags of sand every day. After a few days, all the cement was used up, leaving 120 bags of sand. How many bags of sand and cement are there?
Think about solving problems:
According to the known conditions, only 30 bags of cement and 30×2 bags of sand can be used up at the same time. But now only 40 bags of sand are used every day, and even fewer bags (30×2-40) are used, so the total is 120 bags of sand. Therefore, according to the number of less sand bags used in 120 bag, the service days can be calculated. Then you can get the total number of bags of sand and cement.
Answer:
Solution: Days when cement is used up:
120 ÷ (30× 2-40) =120 ÷ 20 = 6 (days)
Total number of cement bags:
30×6= 180 (bag)
Total number of bags of sand:
180×2=360 (bag)
Answer: 180 bags of cement and 360 bags of sand are brought in.
19, the school bought five thermos bottles and 10 teacups, and * * * used 90 yuan money. The price of each thermos is four times that of each teacup. How much is each thermos and teacup?
Think about solving problems:
According to the calculation that the price of each thermos is four times that of each teacup, the price of five thermos can be converted into the price of 20 teacups. In this way, the 90 yuan money for five thermos bottles and 10 teacups can be regarded as the money for 30 teacups.
Answer:
Solution: Price of each teacup:
90÷(4×5+ 10)=3 (yuan)
Price of each thermos:
3×4= 12 (yuan)
A: each thermos 12 yuan, each teacup 3 yuan.
20. The sum of two numbers is 572, and one of them is 0 of several digits. After removing 0, it is the same as the second addend. What are these two numbers?
Think about solving problems:
It is known that several digits of an addend are 0. If 0 is removed, it will be the same as the second addend. It is known that the first addend is 10 times of the second addend, so the sum of the two addends is 572 times of the second addend.
Answer:
Solution: The first addend:
572÷( 10+ 1)=52
The second addend:
52× 10=520
A: These two addends are 52 and 520 respectively.
2 1. Weight of a barrel of oil16kg. After half use, the barrel weighs 9 kilograms. How much does this bucket weigh?
Think about solving problems:
According to the known conditions, the difference between 16 kg and 9 kg is exactly the weight of half a barrel of oil. 9 kg is the weight of half a barrel of oil and barrel, and the weight of half a barrel of oil is the weight of barrel.
Answer:
Solution: 9-( 16-9)=9-7=2 (kg)
A: This bucket weighs 2 kilograms.
22. Weight of a barrel of oil 10 kg. After pouring out half, the barrel weighs 5.5 kilograms. How many kilograms of oil are there?
Think about solving problems:
According to the known conditions, the difference between 10 kg and 5.5 kg is exactly the weight of half a barrel of oil, and then multiplied by 2 is the weight of the original oil.
Answer:
Solution: (10-5.5)×2=9 (kg)
A: There used to be 9 kilograms of oil.
23. It is known that the walking speed ratio of Xiaoming and Xiao Qiang is 2: 3, and that of Xiao Qiang and Xiaogang is 4: 5. It is known that Xiao Gang walks 420 meters more than Xiao Ming in 10 minute, so how many meters does Xiao Ming walk less than Xiao Qiang in 20 minutes?
Analysis:
According to the conditions, the speed ratio of Xiaoming, Xiaoqiang and Xiaogang is 2× 4: 3× 4: 5× 3 = 8:12:15. According to "Xiao Gang walked 420 meters more than Xiao Ming in 10 minute", Xiao Ming walked for 420 minutes in 10 minute. Xiao Ming walked less than Xiao Qiang in 20 minutes: [480× (12-8) ÷ 8 ]× 2 = 480 meters, only to find that Xiao Ming walked less than Xiao Qiang in 20 minutes, which happened to be the distance that Xiao Ming 10 walked. The method should be simpler.
Another method:
If Xiao Qiang's unit is "1", then Xiaoming is 2/3 of Xiao Qiang's and Xiaogang is 5/4 of Xiao Qiang's, then Xiao Qiang's 10 minute is 420 ÷ (5/4-2/3) = 720m. Xiaoming's 10 minute is less than Xiao Qiang's 1-2/ minute.