1, according to the meaning of the question, 90*( 1-60%)=36, so there is 70*( 1-60%)=28, and the actual fuel consumption is 28kg.

This is a bit complicated. Let's assume that the fuel consumption is reduced by X kilograms, so the fuel consumption is 90-X kilograms.

Then, according to "every decrease in lubricating oil consumption 1kg, the reuse rate of oil consumption will increase 1.6%".

The reuse rate of the obtained oil is (60+ 1.6X)%, so there is.

(90-X)*[ 1-(60+ 1.6X)%]= 12

(X-90)*(X-25)=750

= & gtx^2- 1 15x+ 1500=0，

Get X= 100 or X= 15, obviously X= 15,

Therefore, the fuel consumption is 75 kg and the oil reuse rate is 84%.

Responder: Aston French Navy-Magic Tutor 10.