2.8/9 × 15/36 + 1/27
3. 12× 5/6 – 2/9 ×3
4.8× 5/4 + 1/4
5.6÷ 3/8 – 3/8 ÷6
6.4/7 × 5/9 + 3/7 × 5/9
7.5/2 -( 3/2 + 4/5 )
8.7/8 + ( 1/8 + 1/9 )
9.9 × 5/6 + 5/6
10.3/4 × 8/9 - 1/3
1 1.7 × 5/49 + 3/ 14
12.6 ×( 1/2 + 2/3 )
13.8 × 4/5 + 8 × 1 1/5
14.3 1 × 5/6 – 5/6
15.9/7 - ( 2/7 – 10/2 1 )
16.5/9 × 18 – 14 × 2/7
17.4/5 × 25/ 16 + 2/3 × 3/4
18. 14 × 8/7 – 5/6 × 12/ 15
19. 17/32 – 3/4 × 9/24
20.3 × 2/9 + 1/3
2 1.5/7 × 3/25 + 3/7
22.3/ 14 ×× 2/3 + 1/6
23. 1/5 × 2/3 + 5/6
24.9/22 + 1/ 1 1 ÷ 1/2
25.5/3 × 1 1/5 + 4/3
26.45 × 2/3 + 1/3 × 15
27.7/ 19 + 12/ 19 × 5/6
28. 1/4 + 3/4 ÷ 2/3
29.8/7 × 2 1/ 16 + 1/2
30. 10 1 × 1/5 – 1/5 × 2 1
3 1.50+ 160÷40 (58+370)÷(64-45)
32. 120- 144÷ 18+35
33.347+45×2-4 160÷52
34(58+37)÷(64-9×5)
35.95÷(64-45)
36. 178- 145÷5×6+42 420+580-64×2 1÷28
37.8 12-700÷(9+3 1× 1 1) ( 136+64)×(65-345÷23)
38.85+ 14×( 14+208÷26)
39.(284+ 16)×(5 12-8208÷ 18)
40. 120-36×4÷ 18+35
4 1.(58+37)÷(64-9×5)
42.(6.8-6.8×0.55)÷8.5
43.0. 12× 4.8÷0. 12×4.8
44.(3.2× 1.5+2.5)÷ 1.6 (2)3.2×( 1.5+2.5)÷ 1.6
45.6- 1.6÷4= 5.38+7.85-5.37=
46.7.2÷0.8- 1.2×5= 6- 1. 19×3-0.43=
47.6.5×(4.8- 1.2×4)= 0.68× 1.9+0.32× 1.9
48. 10. 15- 10.75×0.4-5.7
49.5.8×(3.87-0. 13)+4.2×3.74
50.32.52-(6+9.728÷3.2)×2.5
5 1.[(7. 1-5.6)×0.9- 1. 15] ÷2.5
52.5.4÷[2.6×(3.7-2.9)+0.62]
53. 12×6÷( 12-7.2)-6 (4) 12×6÷7.2-6
54.3/7 × 49/9 - 4/3
55.8/9 × 15/36 + 1/27
56. 12× 5/6 – 2/9 ×3
57.8× 5/4 + 1/4
58.6÷ 3/8 – 3/8 ÷6
59.4/7 × 5/9 + 3/7 × 5/9
60.5/2 -( 3/2 + 4/5 )
6 1.7/8 + ( 1/8 + 1/9 )
62.9 × 5/6 + 5/6
63.3/4 × 8/9 - 1/3
64.7 × 5/49 + 3/ 14
65.6 ×( 1/2 + 2/3 )
66.8 × 4/5 + 8 × 1 1/5
67.3 1 × 5/6 – 5/6
68.9/7 - ( 2/7 – 10/2 1 )
69.5/9 × 18 – 14 × 2/7
70.4/5 × 25/ 16 + 2/3 × 3/4
7 1. 14 × 8/7 – 5/6 × 12/ 15
72. 17/32 – 3/4 × 9/24
73.3 × 2/9 + 1/3
74.5/7 × 3/25 + 3/7
75.3/ 14 ×× 2/3 + 1/6
76. 1/5 × 2/3 + 5/6
77.9/22 + 1/ 1 1 ÷ 1/2
78.5/3 × 1 1/5 + 4/3
79.45 × 2/3 + 1/3 × 15
80.7/ 19 + 12/ 19 × 5/6
8 1. 1/4 + 3/4 ÷ 2/3
82.8/7 × 2 1/ 16 + 1/2
83. 10 1 × 1/5 – 1/5 × 2 1
84.50+ 160÷40
85. 120- 144÷ 18+35
86.347+45×2-4 160÷52
87(58+37)÷(64-9×5)
8.95÷(64-45)
89. 178- 145÷5×6+42
90.8 12-700÷(9+3 1× 1 1)
9 1.85+ 14×( 14+208÷26)
43. 120-36×4÷ 18+35
44.(58+37)÷(64-9×5)
45.(6.8-6.8×0.55)÷8.5
46.0. 12× 4.8÷0. 12×4.8
47.(3.2× 1.5+2.5)÷ 1.6
48.6- 1.6÷4= 5.38+7.85-5.37=
49.7.2÷0.8- 1.2×5= 6- 1. 19×3-0.43=
50.6.5×(4.8- 1.2×4)=
5 1.5.8×(3.87-0. 13)+4.2×3.74
52.32.52-(6+9.728÷3.2)×2.5
53.[(7. 1-5.6)×0.9- 1. 15] ÷2.5
54.5.4÷[2.6×(3.7-2.9)+0.62]
55. 12×6÷( 12-7.2)-6
56. 12×6÷7.2-6
57.0.68× 1.9+0.32× 1.9
58.58+370)÷(64-45)
59.420+580-64×2 1÷28
60. 136+6×(65-345÷23)
15- 10.75×0.4-5.7
62. 18. 1+(3-0.299÷0.23)× 1
63.(6.8-6.8×0.55)÷8.5
64.0. 12× 4.8÷0. 12×4.8
65.(3.2× 1.5+2.5)÷ 1.6
66.3.2×6+( 1.5+2.5)÷ 1.6
67.0.68× 1.9+0.32× 1.9
68. 10. 15- 10.75×0.4-5.7
69.5.8×(3.87-0. 13)+4.2×3.74
70.32.52-(6+9.728÷3.2)×2.5
7 1.[(7. 1-5.6)×0.9- 1. 15] ÷2.5
72.5.4÷[2.6×(3.7-2.9)+0.62]
73. 12×6÷( 12-7.2)-6
74. 12×6÷7.2-6
75.33.02-( 148.4-90.85)÷2.5
1) 76.(25%-695%- 12%)*36
77./4*3/5+3/4*2/5
78. 1- 1/4+8/9/7/9
79.+ 1/6/3/24+2/2 1
The sixth grade off-type calculation problem has an answer! :wenku . Baidu ./view/05d 96928 BD 64783 e 09 122 b 79。
Kneel down ... the answer to the sixth grade off-type calculation problem1.45+15× 6 =135.
2.250÷5×8=400
3.6×5÷2×4=60
4.30×3+8=98
5.400÷4+20×5= 200
6. 10+ 12÷3+20=34
7.(80÷20+80)÷4=2 1
8.70+( 100- 10×5)= 120
9.360÷40+ 10= 19
10.40×20-200= 600
1 1.(80-25)*2= 1 10
12.70+45= 1 15
13.90×2÷3= 60
14. 16×6÷3= 32
15.300×6÷9= 200
16.540÷9×7=420
17.30×20÷ 15= 20
18.400÷4×7= 700
19.(350-80)÷9= 30
20. 160+70+50=280
2 1. 18-64÷8= 10
22.42÷6+20=27
23.40-5×7= 5
24.80+60÷3= 100
25.4 1+ 18÷2= 50
26.75- 1 1×5= 20
27.42+7-29= 20
28.5600÷80=70
29.25× 16÷4= 100
30. 120×25÷5= 600
3 1.36× 1 1÷3= 132
32. 1025÷25×8=328
33.336+70-6= 400
34.25×9×4= 900
35.200-33×3= 10 1
36.3020- 10 10=20 10
37. 12×50+ 10= 6 10
38.25×8+ 199= 399
39.23× 1 1- 13= 240
40. 125÷25-5=0
4 1.4200-2200+200=2200
42.220+80- 150= 150
43.20×8×5= 800
44.600-3×200=0
45.20+20÷2= 30
46.35-25÷5= 30
47.36+8-40= 4
1)25%* 132+ 1/4*8 2)32*0. 125*25
= 1/4* 132+ 1/4*8 =(4+8)*0. 125*25
= 1/4*( 132+8) =(4*25)*(8*0. 125)
= 1/4* 140 = 100* 1
=35 = 1000
3)75%*76+25*4+0.75* 12
=3/4*76+3/4* 12+25*4
=3/4*88+ 100
= 166
4)3200* 1/8÷2/5+ 1270 5)(2/3+4/5)*7/6
=400*5/2+ 1270 =22/ 15*7/6
= 1000+ 1270 =77/45
=2270
5)6*( 1/2+2/3) 6) 132*(44÷ 176)
=6* 1/2+6*2/3 = 132* 1/4 =33
=3+4
=7
7)72.25%*99+75.25%
=75.25%*99+75.25%* 1
=75.25%*(99+ 1)
=75.25%* 100
=75.25
①2700×(506-499)÷900 ②33.02-( 148.4-90.85)÷2.5
=2700×7÷900 =33.02-57.55÷2.5
= 18900÷900 =33.02-23.02
=2 1 = 10
③( 1÷ 1- 1)÷5. 1 ④ 18. 1+(3-0.299÷0.23)× 1
=( 1- 1)÷5. 1 = 18. 1+ 1.7x 1
=0÷5. 1 = 18. 1+ 1.7
=0 = 19.8
The answer to the sixth grade score off-type calculation problem is 7/25×4/9+7/25×5/9.
=7/25×(4/9+5/9)
=7/25× 1
=7/25
60×( 1/ 12+ 1/ 15+ 1/4)
=60× 1/ 12+60× 1/ 15+60× 1/4
=5+4+ 15
=24
(5/ 12-3/8)×72
=5/ 12×72-3/8×72
=30-27
=3
6/7-5/24÷7/ 12
=6/7-5/24× 12/7
= 12/ 14-5/ 14
=7/ 14
= 1/2
[3/4×(7/ 16- 1/4)]÷9/ 13
=3/4×(7/ 16-4/ 16)× 13/9
= 1/4×3/ 16× 13/3
= 13/64
2/3-7/8+ 1/3
=(2/3+ 1/3)-7/8
= 1-7/8
= 1/8
5/6-(3/7- 1/6)
=(5/6+ 1/6)-3/7
= 1-3/7
=4/7
1- 1/3-2/3
= 1-( 1/3+2/3)
= 1- 1
=0
1+3/5- 1/ 10
= 1+6/ 10- 1/ 10
= 1+ 1/2
= 1 and 1/2
3/8- 12/ 13+5/8
=3/8+5/8- 12/ 13
= 1- 12/ 13
= 1/ 13
1-( 1/2-3/4)
= 1+3/4-2/4
= 1+ 1/4
=5/4
1- 1/2- 1/4
= 1/2- 1/4
=2/4- 1/4
= 1/4
2/7-8/9+5/7
=(2/7+5/7)-8/9
= 1-8/9
= 1/9
2- 1/4-3/4
=2-( 1/4+3/4)
=2- 1
= 1
1/2-(3/8- 1/2)
= 1/2+ 1/2-3/4
= 1-3/8
=5/8
2.64× 1.7-2.64×0.7
=2.64×( 1.7-0.7)
=2.64× 1
=2.64
3 1.5× 1.07-3. 15×0.7
=3. 15× 10.7-3. 15×0.7
=3. 15×( 10.7-0.7)
=3. 15× 10
=3 1.5
2.7×5.7-2.7+5.3×2.7
=2.7×(5.7- 1+5.3)
=2.7× 10
=27
0.625÷0. 125×0.8
=(0.625×0.8)×8÷(0. 125×8)
=0.5×8÷ 1
=4
18.6×6. 1+3.9× 18.6
= 18.6×(6. 1+3.9)
= 18.6× 10
= 186
The answer to the sixth grade off-type calculation problem is 0.4× 125×25×0.8.
=(0.4×25)×( 125×0.8)
= 10× 100= 1000
1.25×(8+ 10)
= 1.25×8+ 1.25× 10
= 10+ 12.5=22.5
9 123-( 123+8.8)
=9 123- 123-8.8
=9000-8.8
=899 1.2
1.24×8.3+8.3× 1.76
=8.3×( 1.24+ 1.76)
=8.3×3=24.9
9999× 100 1
=9999×( 1000+ 1)
=9999× 1000+9999× 1
= 10008999
14.8×6.3-6.3×6.5+8.3×3.7
=( 14.8-6.5)×6.3+8.3×3.7
=8.3×6.3+8.3×3.7
8.3×(6.3+3.7)
=8.3× 10
=83
1.24+0.78+8.76
=( 1.24+8.76)+0.78
= 10+0.78
= 10.78
933- 157-43
=933-( 157+43)
=933-200
=733
482 1-998
=482 1- 1000+2
=3823
I32× 125×25
=4×8× 125×25
=(4×25)×(8× 125)
= 100× 1000
= 100000
9048÷268
=(2600+2600+2600+ 1248)÷26
=2600÷26+2600÷26+2600÷26+ 1248÷269
= 100+ 100+ 100+48
=348
288 1÷ 43
=( 1290+ 159 1)÷ 434
= 1290÷43+ 159 1÷43
=30+37
3.2×42.3×3.75- 12.5×0.423× 16
=3.2×42.3×3.75- 1.25×42.3× 1.6
=42.3×(3.2×3.75- 1.25× 1.6)
=42.3×(4×0.8×3.75- 1.25×4×0.4)
=42.3×(4×0.4×2×3.75- 1.25×4×0.4)
= 42.3×(4x 0.4x 7.5- 1.25 x4 0.4)
=42.3×[4×0.4×(7.5- 1.25)]
=42.3×[4×0.4×6.25]
=42.3×(4×2.5)
=4237
1.8+ 18÷ 1.5-0.5×0.3
= 1.8+ 12-0. 15
= 13.8-0. 15
= 13.65
6.5×8+3.5×8-47
=52+28-47
=80-47
(80-9.8) × 2/5- 1.32
=70.2X2/5- 1.32
=28.08- 1.32
=26.76
8×7 4÷[ 1÷(3.2-2.95)]
=8×4/7÷[ 1÷0.25]
=8×4/7÷4
=8/7
2700×(506-499)÷900
=2700×7÷900
= 18900÷900
=2 1
33.02-( 148.4-90.85)÷2.5
=33.02-57.55÷2.5
=33.02-23.02
= 10
( 1÷ 1- 1)÷5. 1
=( 1- 1)÷5. 1
=0÷5. 1
=0
18. 1+(3-0.299÷0.23)× 1
= 18. 1+ 1.7× 1
= 18. 1+ 1.7
= 19.8
Others look for it from books. I wrote 2 1. I agree with 1| Comment 2011-2-116: 44. I know 7788 1 1 | level.
Simple calculation of sixth grade in primary school
1.(1/69+2/7 1) times 23+25 divided by 71.
= 1/69*23+2/7 1*23+25/7 1
= 1/3+(46/7 1+25/7 1)
= 1/3+ 1
=4/3
2.( 1+ 1/2) times (1-kloc-0//2) times (1+ 1/3) times (1-kloc)
=3/2* 1/2*4/3*2/3...* 10/9*8/9
= 1/2* 10/9 (all intermediate ones are invited)
=5/9
3. 1/2 times 3+ 1/3 times 4+...+119 times 20.
= 1/2- 1/3+ 1/3- 1/4+...+ 1/ 19- 1/20
= 1/2- 1/20
=9/20
4. 1/27+505/2727+ 13 13 13/272727
= 1/27+5* 10 1/(27* 10 1)+ 13* 10 10 1/(27* 10 10 1)
= 1/27+5/27+ 13/27
= 19/27
5. 100-98+96-94+....+4-2
=( 100-98)+(96-94)+...(4-2)
= 2+2+...+2 (* * has 25)
=2*25
=50
The sixth grade calculation problem has an answer. 2. Two fifths of the number A is three thirds more than one seventh. What is the number a? how much is it?
3. 1.8 is five times, which is 4.5 less than 75% of a number. What's this number?
4.35 divided by 40 times the quotient? What's the difference between a fifth?
5. What is the quotient of1.3 and four fifths divided by the difference between 3 and two thirds?
6. In a division formula, both quotient and b are 5, and the sum of dividend, divisor, quotient and b is 8 1. What are dividend and divisor?
7. Four-nineths of a certain number is 1.6, which is more than five-thirds of 1.2. What's this number?
8. 1.5 times of a number is 6 times of the sum of 3. 1 and 0.5. What's this number?
9.4.5 Multiply the sum of three eighth quotients divided by eight and then added by eight? What is the result?
10. What is the quotient of three-ninth times two-thirds minus 1.5 and then divided by 1.5?
1 1.a number is 56/3, and five sevenths of B number is 40. What are numbers?
Best answer band equation
1. Let this number be x.
6.4x+2.6=6. 1
6.4 times =3.5 times
x=0.546875
2. Let the number of solutions be x.
2x-7/5-65438/7+0x = 3/2。
Eight out of thirty 8x = three out of two
X = 12 in x=35.
Let this number be x.
75%x- 1.8×5=4.5
75%x×9=4.5
x=6
4.35÷40× (one quarter) =0.4375
5.( 1.3+ 4/5) ÷(3- 2/3) = 65438+9/00
6. Omit (not)
7. let this number be X.
4/9 x- 1.2 x 5/3 = 1.6
4/9 x- 2/5 = 1.6
4/9 x=2
X= 9/2
8. let this number be X.
1.5x=(3. 1+0.5)×6
1.5x=3.6×6
1.5x=2 1.6
x= 14.4
9.(4.5÷ 3/8 +8)×6= 120
10.(9/2× 2/3 - 1.5)÷ 1.5= 1.
1 1 .56 Three thirds (five sevenths of forty) = one third.
The question is quite difficult, hehe. Finally, you must choose me!
Homework 3 (Chapters 5-7) 1. True or false 1, × 2, × 3, √ 4, × 5, √ 6, √ 7, √ 8, × 2, multiple choice questions 1, A 2, C 3, D 4, C 5, C 6, B 7. Multiple choice questions 1, ABCD 2, ACD 3, BC 4, ABCE 5, BDE 6, AD 7, ABCD 8, BCDE 9, ABD 10, ACE IV, short answer questions 1, what is sampling error? What are the factors that affect the sampling error? A: Sampling error refers to the absolute deviation between sampling index and total index due to accidental factors of sampling, which makes the structure of sample unit insufficient to represent the whole unit. The factors that affect the sampling error are: the difference of the mark value of each unit in the whole, the number of units in the sample, the sampling method and the organization form of the sampling survey. 2. What are the sampling average error and sampling limit error? What is the relationship between the two? A: The average sampling error is an indicator reflecting the overall level of sampling error; Sampling limit error is an index reflecting the maximum range of sampling error, and there are both connections and differences between them. The relationship between them is: the limit error is calculated on the basis of sampling average error, that is; The difference between them is: (1) has different meanings; (2) The factors affecting the error are different; (3) Different calculation methods. 3. Please write a brief formula of the correlation coefficient, and explain the range of the correlation coefficient and its judgment standard. A: The simple formula of the correlation coefficient: (1) The numerical range of the correlation coefficient is between-1 and+1, that is, (2) the judgment criteria:,; Not relevant, completely relevant. 4. What is the prerequisite for fitting the regression equation yc=a+bx? Write the calculation formulas of parameters A and B and explain the economic significance. A: The requirements for fitting the linear regression equation are: (1) There is indeed a linear correlation between the two variables; (2) The correlation between two variables must be significant; (3) Find suitable parameters A and B, so that the determined regression equation can minimize the square sum of deviation between the actual Y value and the corresponding theoretical value. In the regression equation, parameter A represents the starting point of a straight line, which is called the longitudinal intercept of a straight line mathematically, and it represents the constant term of y when x=0. Parameter b is called regression coefficient, which indicates the average increase of dependent variable y when independent variable x increases by one unit. The sign of regression coefficient is consistent with the sign of correlation coefficient, so we can judge the correlation direction of two variables from the sign of regression coefficient. Calculations of intransitive verbs 1. See the second calculation question on page 344 of the study guide for the answer. For the answer, please refer to the eighth calculation problem on page 348 of the study guide. For the answer, please refer to the calculation question 17 on page 352 of the study guide. 4. Solution: (1) Sample qualification rate = average sampling error = (2) Sampling limit error △p= product qualification rate interval: lower limit =p-△p= upper limit =p-△p= 5. See the calculation on page 73 of the study guide for the answer. For the answer, please refer to the third calculation question on page 360 of the study guide. 7. For the answer, please refer to the seventh calculation question on page 363 of the study guide.
1. 1/4 + 3/4 ÷ 2/3
2.8/7 × 2 1/ 16 + 1/2
3. 10 1 × 1/5 – 1/5 × 2 1
4.3/7 × 49/9 - 4/3
5.8/9 × 15/36 + 1/27
6. 12× 5/6 – 2/9 ×3
7.8× 5/4 + 1/4
8.6÷ 3/8 – 3/8 ÷6
9.4/7 × 5/9 + 3/7 × 5/9
10.5/2 -( 3/2 + 4/5 )
1 1.7/8 + ( 1/8 + 1/9 )
12.9 × 5/6 + 5/6
13.3/4 × 8/9 - 1/3
14.7 × 5/49 + 3/ 14
15.6 ×( 1/2 + 2/3 )
16.8 × 4/5 + 8 × 1 1/5
17.3 1 × 5/6 – 5/6
18.9/7 - ( 2/7 – 10/2 1 )
19.5/9 × 18 – 14 × 2/7
20.4/5 × 25/ 16 + 2/3 × 3/4
2 1. 14 × 8/7 – 5/6 × 12/ 15
22. 17/32 – 3/4 × 9/24
23.3 × 2/9 + 1/3
24.5/7 × 3/25 + 3/7
25.3/ 14 ×× 2/3 + 1/6
26. 1/5 × 2/3 + 5/6
27.9/22 + 1/ 1 1 ÷ 1/2
28.5/3 × 1 1/5 + 4/3
29.45 × 2/3 + 1/3 × 15
30.7/ 19 + 12/ 19 × 5/6