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The 24th International Congress of Mathematicians
Let the short right angle side of a triangle be x.

∫S cube = 125

∴ side length of a small square = 15

The other right side of the right triangle is x+ 15.

∫S big square = 1

∴ side length of a big square = 1

According to Pythagorean theorem, x2+(x+ 15)2= 12.

The solution is x=35.

∴sinθ=35,cosθ=45

∴sin2θ-cos2θ=-725

So choose d