∫S cube = 125
∴ side length of a small square = 15
The other right side of the right triangle is x+ 15.
∫S big square = 1
∴ side length of a big square = 1
According to Pythagorean theorem, x2+(x+ 15)2= 12.
The solution is x=35.
∴sinθ=35,cosθ=45
∴sin2θ-cos2θ=-725
So choose d
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