y = 5+π/3
therefore
x= 1+t/2
y=5+t√3/2
L is y-5=tanπ/3(x- 1).
y=√3x+5-√3
x-y-2√3=0
So x-√3x-5+√3-2√3=0
( 1-√3)x=5+√3
x=(5+√3)/( 1-√3)=-4-3√3
y=√3x+5-√3=-4-5√3
So the intersection (-4-3√3, -4-5√3)