y = 5+π/3

therefore

x= 1+t/2

y=5+t√3/2

L is y-5=tanπ/3(x- 1).

y=√3x+5-√3

x-y-2√3=0

So x-√3x-5+√3-2√3=0

( 1-√3)x=5+√3

x=(5+√3)/( 1-√3)=-4-3√3

y=√3x+5-√3=-4-5√3

So the intersection (-4-3√3, -4-5√3)