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20 12 an answer to mathematics
1 1. solution: set the sales volume to increase by x compared with the original price.

( 1-20%)( 1+x)= 1

80% + 80%x = 1

80%x = 1 - 80%

80%x = 20%

x = 20% ÷ 80%

x = 25%

A: The sales volume will increase by 25% over the original price.

12. 1) solution: let the per capita quota be x pieces.

(4x+20)/4=(6x-20)/5

5(4x+20)=4(6x-20)

20x+ 100=24x-80

-4x=- 180

x=45

A: The per capita quota this month is 45 yuan.

2) Solution: Let the per capita quota of this month be y pieces.

(4y+20)/4=2+(6y-20)/5

5(4y+20)=40+4(6y-20)

20y- 100=40+24y-80

-4y=- 140

y=35

A: The per capita quota this month is 35 yuan.

3) Solution: Assume that the per capita quota this month is m pieces.

(4m+20)/4=-2+(6m-20)5

5(4m+20)=-40+4(6m-20)

20m+ 100=-40+24m-80

-4m=-220

m=55

A: The per capita quota this month is 55 yuan.

13. 1) solution: make him ***x years old.

1/6x+ 1/ 12x+ 1/7x+5+ 1/2x+4 = x

x=84

A: He is 84 years old.

2)84×( 1/6+ 1/ 12+ 1/7)+5

=33+5

=38 years old

A: He became a father at the age of 38.

3)84-4=80 (years old)

He was 80 when his son died.