Suppose these three numbers are a b c.

The two digits of a and b are10a+b10b+a+00b+a.

The two-digit number consisting of b c is10b+c10c+b+00c+b.

The two digits of c a are10c+a10a+c.

These six numbers add up to 22a+22b+22c=22(a+b+c).

The sum of these three numbers is a+b+CB+C.

22(a+b+c)/(a+b+c)=22

For example, these three numbers are 2, 4 and 5 respectively.

The two digits of 2 and 4 are 24 and 42, so are they 10X2+4 and 10X4+2? When you put the number in the tenth place, multiply it by 10, which means it is a ten-digit number, and you don't need to multiply it.

etc