Suppose that the number of people who join the math group alone is S, the number of people who join the chemistry group alone is H, and the number of people who join the math and chemistry groups at the same time is X, then: S+X+6 = 26...( 1).
H+X+4= 13......(2)
S+H+X+ 15=36......(3)
Solutions of contingency (1), (2) and (3): S= 12, X=8, H= 1.
Therefore, eight students take part in the math and chemistry groups at the same time. ?
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