1. A factory needs to recruit workers in positions A and B 150, and the monthly salary is 600 yuan and 1000 yuan respectively. Now it is required that the number of workers in B is not less than twice that of A, so how many workers in A can be recruited to make the minimum monthly wage paid?

2. The coordinate of the intersection of the linear functions Y 1=3x+3 and Y2=-2x+8 in the same rectangular coordinate system is (1, 6). Then when y 1 >; The range of Y2 and x is ()

A, x is greater than or equal to 1 B, x= 1 C, x.

Solution: 1, assuming that type A workers recruit X people, then type B workers recruit (150-X) people, assuming that the total salary is Y yuan, then:

y = 600 X+ 1000( 150-X)= 150000-400 X

According to the known information, there are: 150-X≥2X, and X≤50.

In the above linear function, y decreases with the increase of x, so when x is the largest, y is the smallest.

Therefore, when X=50, the minimum value of y is 130000.

2、

Choose d because when x > 1, the image of Y 1 is above Y2.