Assign three people to four rooms, and the total number of situations is:
A(4,3)=24
/kloc-Room 0/,Room 2 and Room 3 each have one person, and the number of people is as follows:
A(3,3)=6
So 1 room 2, room 3, the probability of one person is
P=6/24= 1/4。
(2)
(4*3*2)/4*4*4=0.375
It happened that there was a person in each of the three rooms. The first person has four choices, the second person has three choices, and the third person has two choices, namely 4*3*2.
Three people are assigned to four rooms with the same probability, and there is no limit to which room three people can choose. There are 4*4*4 options.
(4*3*2)/4*4*4=0.375