Assign three people to four rooms, and the total number of situations is:

A(4，3)=24

/kloc-Room 0/,Room 2 and Room 3 each have one person, and the number of people is as follows:

A(3，3)=6

So 1 room 2, room 3, the probability of one person is

P=6/24= 1/4。

(2)

(4*3*2)/4*4*4=0.375

It happened that there was a person in each of the three rooms. The first person has four choices, the second person has three choices, and the third person has two choices, namely 4*3*2.

Three people are assigned to four rooms with the same probability, and there is no limit to which room three people can choose. There are 4*4*4 options.

(4*3*2)/4*4*4=0.375