An archer shoots ten arrows, and the number of rings hit is 6, 7, 8, 9, 10, 6, 7, 8, 9, 10 respectively.

The archer shot ten arrows, and the number of rings he hit was 7, 8, 9, 7, 8, 9, 7, 8, 9 and 8 respectively.

Both of them have an average score of 8 rings. So whose is more stable? It can be measured by variance.

What is the variance of s? The average value is expressed in m, s? = 1/n[(x 1-m)？ +(x2-m)？ +.......+(xn-m)？ ]

Variance of group a data

s？ = 1/ 10[(6-8)? +(7-8)? +(8-8)? +(9-8)? +( 10-8)? +(6-8)? +(7-8)? +(8-8)? +(9-8)? +( 10-8)? ]= 1

Variance of group b data

s？ = 1/ 10[(7-8)? +(8-8)? +(9-8)? +(7-8)? +(8-8)? +(9-8)? +(7-8)? +(8-8)? +(9-8)? +(8-8)? ]=0.6

The data variance of group A is large, indicating that group A is more unstable.

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