Solution 1: (number of rabbit feet × total number of feet-total number of feet) ÷ (number of rabbit feet-number of chicken feet) = number of chickens, and total number of chickens = number of rabbits;

Solution 2: (total number of feet-number of chicken feet × number of chickens) ÷ (number of rabbit feet-number of chicken feet) = number of rabbits, and total number of rabbits = number of chickens.

Chicken and rabbit in the same cage is one of the famous mathematical problems in ancient China. About 1500 years ago, this interesting question was recorded in Sun Tzu's calculation. The book describes it like this:

Today, there are pheasant rabbits in the same cage, with 35 heads above and 94 feet below. Pheasant rabbit geometry?

These four sentences mean:

There are several chickens and rabbits in a cage, counting from the top, 35 heads, counting from the bottom, 94 feet. How many chickens and rabbits are there in each cage?

The essence of this problem is a binary equation. If the teaching method is proper, primary school students can understand the concepts of unknowns and equations and exercise their ability to abstract numbers from application problems. Generally, in the fourth to sixth grades of primary school, the content of one-dimensional linear equation is used to teach.

There is another variation in the same book:

Today, there are beasts with six feet and four feet; Birds, four feet, seventy-six on the top and forty-six on the bottom. Q: What are the geometric shapes of birds and animals? A: Eight animals and seven birds.

The subject conditions include different heads and different feet.