∫a = {x | x = 2m+ 1, m∈Z} ∴A is a group of integers divisible by 2 and 1.
Similarly, b is a set of integers divided by 3 and 1.
So A∩B={ an integer divided by 6 and 1}
2. because "㎡+2m-3 > 0" can't judge its authenticity. That is to say, this statement does not give the value of m, so it cannot be judged.
㎡+2m-3 > 0 is true or false, so ㎡+2m-3 > 0 is an opening statement rather than a proposition.
Note: if this sentence is "㎡+2m-3 > 0 (m 1)", it is a proposition.
I hope LZ can be satisfied with my answer, because I also like Conan.