∫a = {x | x = 2m+ 1, m∈Z} ∴A is a group of integers divisible by 2 and 1.

Similarly, b is a set of integers divided by 3 and 1.

So A∩B={ an integer divided by 6 and 1}

2. because "㎡+2m-3 > 0" can't judge its authenticity. That is to say, this statement does not give the value of m, so it cannot be judged.

㎡+2m-3 > 0 is true or false, so ㎡+2m-3 > 0 is an opening statement rather than a proposition.

Note: if this sentence is "㎡+2m-3 > 0 (m 1)", it is a proposition.

I hope LZ can be satisfied with my answer, because I also like Conan.