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Sixth grade answer mathematics
1.1÷ 20 ÷ 80 =11600 (originally planned to carry one vehicle at a time).

Suppose the rest can be shipped x times. Then,

1/ 1600×20×20+ 1/ 1600×(20+30)x = 1

0.25+ 1/32x= 1

x=24

A: We can deliver the goods after the remaining 24 times.

2.( 1) Suppose two cars meet after x hours. Then,

57x+(57+ 1)x=276

x=2.4

A: After 2.4 hours, the two cars met.

(2) Assuming that it took y hours from the beginning to the distance of 46 kilometers, then,

57x+(57+ 1)x=276-46

x=2

A: The distance from the beginning to 46 kilometers took two hours.

(3) It is 69 kilometers from the beginning to the meeting, and it took Z hours * * *, then,

57x+(57+ 1)x=276-69

x= 1.8

A: It was 69 kilometers from the beginning to the meeting, and it took * * * 1.8 hours.

3.200 ÷10 = 20km/h

120 ÷10 =12km/h

20-12 = 8km/h

8×2 = 16 km/h (this is the speed in still water)

320÷ 16 = 20 hours (hours)

A: It took him 20 hours to sail 320 kilometers in calm water.

4. If the distance between Station A and bilibili is X kilometers, then

(x-65)÷65×58.5=x- 104

x=455

A: The distance between Station A and bilibili is 455 kilometers.

If you don't understand the third or fourth question, please add my qq to 1428289052.