On the whole, it's easy. 2t？ -7t+3=0，
T= 1/2 or 3. (1) If a = 3,3 (x-1) = 3, a=2 (obtained), 3 (x- 1) = 1/2,
Then the other root of X is 1-log3(2)② If a= 1/2,
Similarly, the other root can be obtained as: 1-2log2(3). 2. First, if the denominator is not zero, a ≠ 3 1, a>3. From the image, a x and a (-x) are both increasing, which is obviously 2,0.
3. There is a simple method: assignment method. Let x=0,
F( 1)= 1/2f(0) is substituted to exclude ABC, so the stupid way to choose d is to replace f(x) with the function in ABCD option and then calculate. It is not advisable to take the exam, it is a waste of time.