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Hand-in-hand model of junior high school mathematics
Proof: AE from A is perpendicular to BC in E.

Because △ABC is an isosceles right triangle, BE=CE.

AE is the center line of the hypotenuse, so AE=BE=CE.

In RT△ADE, AD? =AE? +DE?

BD? =(BE-DE)? = Yes? -2BE×DE+DE?

CD? =(CE+DE)? =CE? +2CE×DE+DE?

Because BE=CE, BD +CD? =2BE? +2DE?

2AD? =2AE? +2DE?

Because AE=BE, BD? +CD? =2AD?