So the e coordinate is (3,0)

The slope of the straight line AB =(3-0)/(0+ 1)=3.

The slope of the straight line BE =(3-0)/(0-3)=- 1.

The slope of the straight line BD =(3-4)/(0- 1)= 1.

The slope of the straight line DE =(4-0)/( 1-3)=-2.

So BE⊥BD, so △DEB is a right triangle.

Because △AOB is a right triangle

Therefore, only right triangles are similar to them.

That is, △EOB and △DEB may be similar to △AOB.

AO= 1，BO=3，OE=3，BD=√2，BE=3√2。

So AO:BO= 1:3.

BO:EO= 1: 1

BD:BE=√2:3√2= 1:3

So △DEB is similar to △AOB.