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Answers to Several Problems in Mathematics &; Analysis (online, etc. ! )
1 set of known inequalities 2x-a <1x-2b >; The solution set of 3 is-1

The solution is the solution: solve these two inequalities separately and get:

2x-a & lt; The solution set of 1 is: x

x-2b & gt; The solution set of 3 is x & gt2b+3,

The solution set of the original inequality group is 2b+3.

(a+ 1)/2= 1, so: a= 1,

2b+3=- 1, so: b=-2. 》

therefore

(a+ 1)(b- 1)

=( 1+ 1)(-2- 1)

=2*(-3)

=-6

2 because m+2 >; m- 1,

The solution set of the inequality group X > M- 1 and X > M+2 is X > M+2.

The solution set is x >- 1,

Therefore, m+2=- 1.

m=-3

Thank you. Take it. . . .