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Work out this arithmetic problem.
954-459=495。

Digital black hole 495

As long as three digits are entered, the required digits are different, such as 1 1 1, 222, etc. therefore

You rearrange these three numbers by size to get the maximum number and the minimum number. Subtract the two to get a new number, rearrange it, subtract it again, and finally get the number 495, which is called a digital black hole.

For example, input 352, arranged at 532 and 235, is subtracted to get 297; Rearrange it into 972 and 279, and subtract it to get 693; Arranged as 963 and 369, subtracted to get 594; Then arrange them into 954 and 459, and subtract them to get 495.

It should be just a number law, and there are many similar ones, such as the four-digit digital black hole 6 174:

Arrange the four digits of a four-digit number into a new number from small to large, and then arrange it into a new number from small to large. Subtract these two numbers and repeat this step. As long as the four digits of the four digits are not repeated, this number will eventually become 6 174.

For example, 3 109, 9310139 = 9171,971179 = 850. And the number 6 174 will also become 6 174,7641-1467 = 6174.

Take any four digits, as long as they are not all the same, and arrange them in descending order to form the largest number as the minuend; According to the ascending order of numbers, take the smallest number for subtraction, and the difference will be 6174; If it is not 6 174, subtract it again according to the above method, and at most it will be 10 to get 6 174.

If the four-digit number is 5679, follow the above method as follows:

9765-5679=4086 8640-4068=4572 7542-2457=5085

8550-5058=3492 9432-2349=7083 8730-3078=5652

6552-2556=3996 9963-3699=6264 6642-2466=4 176

764 1- 1467=6 174