Current location - Training Enrollment Network - Mathematics courses - Mathematical problems, Libra problems
Mathematical problems, Libra problems
To be balanced, both sides must be equal.

* * * is (1+32) * 32/2 = 33 *16 = 528 (g)

Both sides are equal, that is, 528/2 = 264 (grams)

So, if we make up 264 grams, the rest is naturally 264, that is, we have reached a balance.

Simply calculate, 1 to 20g all add up (1+20) * 20/2 = 2 10 (grams), which is not enough for 264g.

2 10+2 1+22+23=276

276-264= 12

That is to say, from 1 to 23g, if12g is removed, it is exactly 264g. Put it aside. Balance the rest on the other side.

Check, (1+23) * 23/2-12 =12 * 23-12 = 276-12 = 264.

Ok.

Of course, the easiest way is to add 1+32, 2+3 1 ... from beginning to end, you get another set of 33 grams and another set of *** 16.

At this time, as long as you ensure that there are 8 groups on both sides, you will definitely balance.