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Four answers are required for mathematics in senior one.
Root number 3sin2x+cos2x

Y= radical 3sin2x+cos2x

=2 (root number 3/2*sin2x+ 1/2*cos2x)

=2(sin2x*cos30+cos2x*sin2x)

= 2 inches (2x+30)

3sinx+4cosx simplification

3sinx+4cosx=√(3? +4? )【sinx*3/√(3? +4? )+cosx*4/√(3? +4? )]

=5[sinx*3/5+cosx*4/5]

Let cosφ=3/5.

So sinφ=√( 1-cos? φ)=√( 1-9/25)=4/5

∴3sinx+4cosx=5(sinx*cosφ+cosx*sinφ)

=5sin(x+φ)