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Analysis on the application of mathematical percentage in the sixth grade of primary school
Analysis on the application of mathematical percentage in the sixth grade of primary school

Percentages are special fractions and cannot be expressed by fractions. Fractions with 100 as the denominator. The following is the percentage application problem of sixth grade mathematics that I sorted out. I hope everyone will read it carefully!

I. Examples of real questions

1.A car travels from A to B. After a certain distance, it is still 2 10 km away from B, so it has traveled 20% of the whole journey. At this time, the ratio of moving distance to non-moving distance is 3: 2. Find the distance between A and B (Question 4 of the 2009 School Selection Examination)

The garden team plans to plant a batch of saplings. Two10 saplings were planted on the first day, and the remaining 20% were planted on the second day. After two days, the total number of saplings has not been completed. How many saplings are there? (20 1 1 Major League Application No.3)

3. A store sells two goods at the same time, and each one wins 30 yuan. During this period, one product made a profit of 20% and the other product lost 20%. Does this store sell these two commodities at a profit or a loss? how much is it? (20 13 Major League Application Question 6)

Second, the test center analysis

Percentage application problem is the most widely used mathematical problem in daily life and production practice, including the calculation of germination rate, qualified rate, interest and profit rate. This kind of knowledge is closely related to life. How to master the characteristics of this kind of problems and use them skillfully and flexibly is a problem that we should think about when studying this kind of problems. In the process of solving problems, we should focus on solving several problems:

(1) Accurately determine the number of units "1".

(2) Determine the type: quantity in "1" × score = quantity corresponding to the score.

Quantity corresponding to fraction rate ÷ fraction rate = quantity unit "1"

The amount corresponding to the score ÷ the amount of the unit "1" = the score.

(3) Determine the corresponding relationship.

Third, draw inferences from others.

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