Details are as follows:
The salt content of the first water is 200× 15%=30 (g).
30+50=80 grams of salt.
80÷250× 100%=32% The answer to the first question.
250+ 150=400 (g) total amount of brine after adding water.
80÷400× 100%=20% The answer to the second question.
200×8%= 16 (g) salt in water to be added.
Add 200- 16= 184 (g) of water.
80+ 16=96 (g) total salt added.
400-80+ 184=504 (g) total amount of water added.
96+504=600 (final total water volume)
96÷600× 100%= 16% The answer to the third question.
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