Find f(x) first. The original function is shifted to the right by 2, 1 to get f(x), so f(x) is shifted to the left by 2, 1 to get the original function, that is, (x-2, f(x)- 1) is on the original function. F (x)-1=1-1((x-2)+2), that is, f (x) = 2-1/x.
Therefore, an=2- 1/an- 1, that is, an-1/an-1,that is,1/(an-1) =
Therefore, bring BN-BN-1= BN-1* (an-1-1) into BN-BN-1=1(an-/kloc-. So this is not a condition. .
(2) if bn-bn- 1 = 1 and b 1=-5/2, it is easy to know that bn = n-7/2, then an =1+1(n-7/2
Make a < 0 get 5/2.
The rest of the time, when n & gt=4, an is always positive, and it obviously decreases with the increase of n, so it is easy to know an >: 1, while a 1=3/5, a2= 1/3, a4=3, an.
Therefore, the minimum value a3=- 1 and the maximum value a4=3.