From the equal circumferential angles on the same circle, we can know that:
In the circle o 1: ∠BCF=∠BAF.
In the circle o2: ∠BAE=∠BDE
∠∠BAE+∠BAF =∠EAF = 39
∴∠BDE+∠BCF=39
∴∠cbd= 180-(∠BCF+∠bde)= 180-39 = 14 1