From the equal circumferential angles on the same circle, we can know that:

In the circle o 1: ∠BCF=∠BAF.

In the circle o2: ∠BAE=∠BDE

∠∠BAE+∠BAF =∠EAF = 39

∴∠BDE+∠BCF=39

∴∠cbd= 180-(∠BCF+∠bde)= 180-39 = 14 1