Current location - Training Enrollment Network - Mathematics courses - Second grade, candy points. If everyone is divided into seven parts, there will be three more. If everyone is divided into 8 capsules, there will be 4 capsules missing. So there are as many children a
Second grade, candy points. If everyone is divided into seven parts, there will be three more. If everyone is divided into 8 capsules, there will be 4 capsules missing. So there are as many children a
Second grade, candy points. If everyone is divided into seven parts, there will be three more. If everyone is divided into 8 capsules, there will be 4 capsules missing. So there are as many children as there are sweets. Is it true what you said?

This is a profit and loss problem in the third-grade Olympiad, which is hard for the second-grade children to accept.

Profit+loss-difference

small profits but quick turnover

(big loss-small loss)

The number of children in this question is: (3+4) (8-7) = 7.

The number of sweets is 7× 7+3 = 52.