& lt 1 & gt； Logarithm of function 2log based on 10 = logarithm of function log based on 100]

Logarithm with base 3 1 =0

Logarithm of 3 with base 9 = Logarithm of 3 with base 3 squared.

= 1/2 times the logarithm based on 3 = 1/2.

2 base 3 logarithm 100+ base 3 logarithm 0.27 = base 3 logarithm (100 * 0.27)= base 3 logarithm 27 =3.

So (1)=3+ 1/2=7/2.

& lt2> It is known that the logarithm of the logarithm based on 2 = m-(logarithmic formula is converted into exponential formula) A m = 2.

Logarithm of 3 based on A = n-(logarithmic formula is converted into exponential formula) A n = 3

Then a2m+n = (a2m) * (an n) = 2 2 * 3 =12.

& lt3 & gt(27/3) 1/3 = root number 3 (generally, accurate numerical values are required for calculation, so it is ok, but it is wrong to use a calculator).

lg 1=0

(lg3)^0= 1

3^log logarithm based on 3 10 = 10.

(27/3)1/3-LG1+(lg3) 0+3 logarithm/logarithm of kloc-0/0 is base 3 = radical number 3+ 1 1.