Math problem in the fourth grade of primary school: Chicken and rabbit are locked together, with 30 heads and 86 feet. How many chickens and rabbits are there respectively?

There is no equation in the fourth grade of primary school, so we can only solve this problem through analysis and exercise children's analytical ability.

The disintegration process is as follows:

1. If a chicken and a rabbit count as two feet, there should be * * * 30 X2 feet =60 feet.

2. The extra 86-60=26 feet must be the extra feet of all rabbits.

3. In other words, each rabbit can grow two feet, so the number of rabbits is: 26/2= 13.

? Then the number of chickens is: 30- 13= 17.

The third question on page 57 of mathematics for the top students in the eighth grade.

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