Methods The second LY ratio method was used. This problem can be logically analogized to a concentration or average matching problem. Let the lowest score among the winning students be A, and the winning students: non-winning students =1:3 = [88-(a-15)]: (a+8-88), and the solution is a=97.25.
Methods Trilie algebra method. Assuming that the lowest score among winners is X, and all students have A, according to "the total score of winners+the total score of non-winners = the total score of all students", it is1/4a (x+8)+3/4a (x-15) = 88a, and the solution is x=97.25.