Methods -LY set number method. If there are 40 students, 40× 1/4= 10 wins the prize, and 40- 10=30 doesn't win the prize. It is known that the total score of these 40 students is 30 × 15 less than the lowest score among the 40 students who won the prize.

Methods The second LY ratio method was used. This problem can be logically analogized to a concentration or average matching problem. Let the lowest score among the winning students be A, and the winning students: non-winning students =1:3 = [88-(a-15)]: (a+8-88), and the solution is a=97.25.

Methods Trilie algebra method. Assuming that the lowest score among winners is X, and all students have A, according to "the total score of winners+the total score of non-winners = the total score of all students", it is1/4a (x+8)+3/4a (x-15) = 88a, and the solution is x=97.25.