∴∠bad= 120 ∴∠acb= 180-∠BAC-∠b = 30
∠∠B = 60∠∠ 1 = 30
∴∠dab+∠b= 120+60 = 180 ∴∠ 1=∠acb
∴AD∥BC (internal dislocation angles are equal and two straight lines are parallel)
I hope this helps ∵∠ ba d +∠ b =120+60 =180.
∴AB∥CD (complementary to the inner angle on the same side, with two straight lines parallel)