Solution: As shown in the figure, cross C into CE⊥AB in E.

CE is the width of the river,

Let CE=x (m), then BE=x+60 (m),

In Rt△BCE,

tan30 =

∴ x=x+60

∴ x = 30 (+1) ≈ 81.96m.

A: The width of the river is about 8 1.96 meters.