We are now looking for it in mutually exclusive events: that is to say, none of them has a 5 or 6.

There are: c (41) * c (41) =16 kinds.

Then: the mutual exclusion probability is: 16/36=4/9.

There is at least one probability of 5 or 6 points: 1-4/9=5/9.

So: n=5/9*30=50/3.