Let x belong to r, y= 1 and get the x power of f(x)=f( 1).

F (1) is more than 0 from the meaning of the question (if f( 1)=0, then f(x) is constant =0, which is inconsistent with the given range).

F( 1/4)) =/power of kloc-0//4 f (1) < 1 so f (1/4).

2 times f( 1) squared = Party A+Party B > 2ab (because A is not equal to B, it cannot be equal).

The square of F( 1) >: Ab takes the logarithm based on f( 1) (because 0

2 & ltab logarithm with base F (1)= a logarithm with base F (1)+b logarithm with base F (1) =f inverse (a)+f inverse (b).

The inverse function of y=f(x) is the logarithm of y=log of x with f( 1) as the base.