Solution: 1, from the meaning of the question
BP= 12-t, BQ=2t, and the height from q to BP is (root number 3)t/2.
RC=6, QC= 12-2t, QC= 12-2t, and the height from q to RC is (root number 3)(6-t).
The area of ∴△BQP is [( 12-t) (root number 3)t/4].
△ The area of △QRC is [3 (root number 3)(6-t)]
The area of △ABC is 36 radicals 3.
S=36 radical 3-[( 12-t) (radical 3)t/4]-[3 (radical 3)(6-t)]
= (root number 3) t 2/4-2 (root number 3)t+30 root number 3
When point Q reaches point C, P and Q stop moving.
The value range of ∴t is (0,6).
Sorry, I didn't catch the meaning of the topic.