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Apr mathematics
I calculated that r is the midpoint of the line segment AC, without adding the unit. )

Solution: 1, from the meaning of the question

BP= 12-t, BQ=2t, and the height from q to BP is (root number 3)t/2.

RC=6, QC= 12-2t, QC= 12-2t, and the height from q to RC is (root number 3)(6-t).

The area of ∴△BQP is [( 12-t) (root number 3)t/4].

△ The area of △QRC is [3 (root number 3)(6-t)]

The area of △ABC is 36 radicals 3.

S=36 radical 3-[( 12-t) (radical 3)t/4]-[3 (radical 3)(6-t)]

= (root number 3) t 2/4-2 (root number 3)t+30 root number 3

When point Q reaches point C, P and Q stop moving.

The value range of ∴t is (0,6).

Sorry, I didn't catch the meaning of the topic.